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Each month, a new set of puzzles will be posted.  Come back next month for the solutions and a new set of puzzles, or subscribe to have them sent directly to you.

## ARITH-Maze puzzle

In the following ARITH-Maze puzzle, go to ‘START’ and proceed through this numerical maze, following instructions as provided, until you get to the ‘FINISH’ box. What number did you finish with? ## Feedback

There are more than one way of doing these puzzles and may well be more than one answer.  Please let me and others know what alternatives you find by commenting below.  We also welcome general comments on the subject and any feedback you'd like to give.

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##### Last month's solutions
 How many complete turns does circle A make to rotate around the outside of circle B once if circle A is one-half the size of circle B. (Note: Diagram is not drawn to scale.) Solution: Note: As circle A rotates once around the outside of stationary circle B, circle A rotates 720º (or 2 to1 as if the length of the circumference of circle B was laid flat as a straight line plus another 360º as it relates to the one rotation around the exterior of circle B. Therefore, circle A rotates a full 1080º (720º + 360º) or 3 complete turns. How many complete turns does circle A make to rotate around the inside of circle B once if circle A is one-half the size of circle B. (Note: Diagram is not drawn to scale.) Solution: Note: As circle A rotates once around the inside of stationary circle B, circle A rotates 720º or 2 to 1 as if the length of the circumference of circle B was laid flat as a straight line minus 360º as it relates to the one rotation around the internal of circle B. Therefore, circle A rotates a full 360º (720º – 360º) or 1 complete turn. To get a square photograph to fit into a rectangular frame, Brian had to trim a 1-inch strip from each of two opposite sides of the photo and a 2-inch strip from each of the other two sides. In all, he trimmed of 64 squire inches. What were the original dimensions of the photograph? Solution: Let X = the side dimension of the square photograph Then, Area of two 1-inch trims = 2 * (H1 * W1) = 2 * (1 * x) = 2x and, Area of two 2-inch trims = 2 * (H2 * W2) = 2 * [(x-2) * 2] = 4x – 8 Therefore, (2x) + (4x – 8) = 64, 6x = 64 + 8 = 72, x = 72/6 = 12 The original dimensions of the photograph was 12 x 12 inches.