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HEXAGONnumeric Puzzle (Level 1)Fit the numbers 1 to 6 in each hexagon so that where a hexagon touches another, the numbers in each of their touching segments are the same. No number is repeated in any hexagon. Solve the puzzle by finding all the missing numbers. 
HEXAGONnumeric Puzzle (Level 2)Fit the numbers 1 to 6 in each hexagon so that where a hexagon touches another, the numbers in each of their touching segments are the same.
Solve the puzzle by finding the Output number. 
HEXAGONnumeric Puzzle (Level 3)Fit the numbers 1 to 6 in each hexagon so that where a hexagon touches another, the numbers in each of their touching segments are the same.
Solve the puzzle by finding the Output number. 
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Last month's solutions
Puzzle One
62 people have taken part in a survey on modes of transport they use to travel to work. They have been asked whether they travel by Car, Train and Bus only or a combination of these three modes of travel.

 Twice as many people use the Car only as use the Car and Train.
 Four more people use the Bus only than the Train only.
 Twice as many people use the Train and Bus as use all three modes.
 The same number of people use the Car and Bus as use the Bus only.
 Thirteen more people use the Car only than the Bus only.
 Two people use all three modes of transport.

 How many people travel by Car only?
 How many people travel by Train only?
 How many people travel by Bus only?
 How many people travel by Car and Bus?
Solution
Let: C = people travel by Car only
T = people travel by Train only
B = people travel by Bus only
(C + T) = people travel by Car & Train
(T + B) = people travel by Train & Bus
(C + B) = people travel by Car & Bus
(C + T + B) = people travel by all 3 modes
Given: C = 2 * (C + T)
B = (T + 4)
(T + B) = 2 * (C + T + B)
(C + B) = B
C = (B + 13)
(C + T + B) = 2,
Then, (T + B) = 2 * 2 = 4
P = Participants = 62 people = C + T + B + (C + T) + (T + B) + (C + B) + (C + T + B)
C + T + B + (C + T) + (T + B) + (C + B) + (C + T + B) = 62
(B + 13) + (B – 4) + B + C/2 + 4 + B + 2 = 62
4B + C/2 + 15 = 62
4B + (B + 13)/2 + 15 = 62, 4.5 B = 62 – 21.5 = 40.5, B = 9,
Then, T = (B – 4) = 5, C = (B + 13) = 22
And (C + T) = C/2 = 22/2 = 11
Puzzle Two
Find the number equivalent for the following alphametic expressions to make the equations true. Each letter is unique with values from 0 to 9. Note: There may be more than one solution.

 ZERO + ONE + TWO = THREE
 TWO + THREE + SEVEN = TWELVE
 THREE + THREE + ONE = SEVEN
 SEVEN + SEVEN + SIX = TWENTY
Solutions:
 9635 + 546 + 185 =10366 &
9635 + 586 + 145 =10366  106 + 19722 + 82524 = 102352 &
104 + 19722 + 82526 = 102352  18299 + 18299 + 479 = 37077
 68782 + 68782 + 650 = 138214