Each month, a new set of puzzles will be posted. Come back next month for the solutions and a new set of puzzles, or subscribe to have them sent directly to you.
MIND-Xpander Logic Problems
- Ship Ahoy – A ship is at anchor. Over its side hangs a rope ladder with rungs a foot apart. The tide rises at the rate of 8 inches per hour. If the ladder was 8 feet above the water level when the tide began to rise, how much of the rope ladder will remain above water after 6 hours?
- Water lilies on a certain lake double in area every twenty-four hours. From the time that the first water lily appears until the lake is completely covered takes 60 days. On what day is the lake half-covered?
The missing numbers are between 1 & 9 with no repeats. The three numbers in each row, when multiplied or times together, equals the totals on the right, and the columns, when multiplied together, equals the totals along the bottom. The multiples of the two diagonals are also given. Solve the puzzle by finding all of the missing numbers that satisfy all of the multiplied results as shown.
HEXAGON-numeric Puzzle (Level 3)
Fit the numbers 1 – 6 in each hexagon and where the hexagon sides touch each other, the numbers in these 2 segments will be the same. No number can be repeated in a hexagon. The numbers in the shaded areas are the sum of the numbers in the 2 or 4 segments that they side with. The numbers in the ‘Input’ and ‘Output’ boxes are the sum of the numbers in the 3 triangular segments that they side with. The numbers in the ‘Sum’ boxes are the sum of the numbers in the 4 segments that they side with. Solve the puzzle and find the ‘Output’ number.
There are more than one way of doing these puzzles and may well be more than one answer. Please let me and others know what alternatives you find by commenting below. We also welcome general comments on the subject and any feedback you'd like to give.
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Last month's solution
MIND-Xpander Logic Problem
ROMAN Arithmetic Puzzles
MMCCLXV – CXXII – XLIV – XCIX = MM
Solution: 2265 – 122 – 44 – 99 = 2000
CCCXXI + DCLIV + CMLXXXVII = MCMLXII
Solution: 321 + 654 + 987 = 1962
DIII + XDXII + CMXXIV + CLXXI = MMX
Solution: 503 + 412 + 924 + 171 = 2010
DCLXVI – DVI + DLV + CCCXXXIII + CDXLIV = MCDXCII
Solution: 666 – 506 + 555 + 333 + 444 = 1492